Question

initially a body is at rest. if its acceleration is 5m/s then the distance travelled in the 18th second is

Answer 1

Just use the basic equations of motion and you’re done. Since ,

u=0(initialvelocity)u=0(initialvelocity)

=>s18−s17=0+(1/2∗a∗((18)2−(17)2))s18−s17=0+(1/2∗a∗((18)2−(17)2))

(u=0ands=u∗t+1/2∗a∗t2)(u=0ands=u∗t+1/2∗a∗t2)

In general distance travelled in nth second is,

Sn=u+(1/2∗a∗(n2)−1/2∗a∗((n−1)2))Sn=u+(1/2∗a∗(n2)−1/2∗a∗((n−1)2))

=>Sn=u+1/2∗a∗(2∗n−1)