Initially a car is moving with speed of 20 ms-1 and covers a distance of 100 m before it comes to rest.On making the initial speed of car 40 ms -1 keeping the acceleration same, the distance
travelled by car before it comes to rest is (1) 200 m (2) 300 m (3) 400 m (4) 800 m
answer with explanation.Help me pls
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Answer:
200 m
Explanation:
s1 / v1 = s2 /v2
( s1 / v1 ) x v2 = s2
s2 = 100 / 20 x 40
s2 = 200 m
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