Question

Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?

Answer 1

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Answer 2

Answer:

3.093 atm

Explanation:

For this you would use the formula

Pv=nRT

P1T2 = P2T1

P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??

(3.20 atm)(290 K) = P2(300 K)

P2 = (3.20 atm)(290 K)/ (300 K) = 3.093 atm