Initially A had Rs.10 more than B . A gives one half of his money to B. B reciprocates and gives one half of his money to A . Now A has Rs.20 more than B .How much do A and B have in total in the beginning?
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Answer:
Rs. 70
Step-by-step explanation:
Given,
A had- a, B had- b, a=b+10, a+b=?
Now,
A gives one half and left with: a-a/2=a/2
B receives from A one his half and now has: b+a/2
Then,
B gives half of his money and is left with: (b+a/2)-(b+a/2)/2=(b+a/2)/2
A now has: a/2+(b+a/2)/2 and it is Rs. 20 more than B:
a/2+b/2+a/4=b/2+a/4 +20
a/2=20
a=40
a=b+10 => b=a-10=30
a+b=40+30=70
A and B had Rs. 70 in the beginning.
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