initially charge Q3 was kept at point a finally moved to point D in a circular path of radius 80 cm about A calculate the work done
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Hey there!
In attached fig. CD is arc , means distance AC and AD are equal.
BD = AD - AB
BD = [ 80-60] = 20 cm
Now by Pythagoras theorem find distance CB
CB^2 = AC^2 + AB^2
CB = 100
Now as we know that work done = change in potential energy
Ui = 1/4 pi € [ q1q2/(0.6) + q1q3/(0.8) +q2q3/(0.10)]
Uf = 1/4 pi €. [ q1q2/(0.6) + q1q3/(0.8) + q2q3/(0.2)]
now find change in U , you'll get your answer.
Note:- final position if q3 is at D so at Uf take distance between q2 and q3 = 20cm I.e 0.2m.
In attached fig. CD is arc , means distance AC and AD are equal.
BD = AD - AB
BD = [ 80-60] = 20 cm
Now by Pythagoras theorem find distance CB
CB^2 = AC^2 + AB^2
CB = 100
Now as we know that work done = change in potential energy
Ui = 1/4 pi € [ q1q2/(0.6) + q1q3/(0.8) +q2q3/(0.10)]
Uf = 1/4 pi €. [ q1q2/(0.6) + q1q3/(0.8) + q2q3/(0.2)]
now find change in U , you'll get your answer.
Note:- final position if q3 is at D so at Uf take distance between q2 and q3 = 20cm I.e 0.2m.
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