Question

Initially, the equilibrium is obtained by taking 2 moles of H, and I, each of 2 moles of HI, so what is the value of K for the following procedure? H, + 1 = 2HI

Answer 1

Explanation:

CHEMISTRY

Evaluate K

p

for the reaction : H

2

+I

2

⇌2HI. 2 moles each of H

2

and I

2

are taken initially equilibrium moles of HI are 2 :

December 27, 2019avatar

Rash Kasyap

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ANSWER

Reaction;

H

2

+I

2

→2HI

K

C

=

(H

2

)(I

2

)

(HI)

2

Initial moles of H

2

and I

2

=2

At equilibrium ,moles of H

2

and I

2

=2-x

At equilibrium moles of HI=2

From reaction x mole of H

2

and I

2

will give 2x mole of 2HI

Then, 2x=2

x=1

K

C

=

(1)(1)

(2)

2

=4