Initially x=-√3/2A and it is moving in positive x direction. Find equation for SHM.
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Answer:
Velocity of particle in SHM is given as v=ω
A
2
−x
2
−(1)
Let new amplitude be A
1
,
as the velocity is doubled at distance x from the center, with angular frequency ω remaining constant.
So, 2v=ω
A
1
2
−x
2
−(2)
From (1) and (2), A
1
=
4A
2
−3x
2
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