Math, asked by yuvvanmuthu, 6 months ago

iniya bought 50kg of fruits consisting of apples and bananas she paid twice as much per kg for the apple as she did for the banana if iniya bought 1800 worth of apples and 700 worth of banana then how many kgs of each fruits did she buy​

Answers

Answered by kevinskolkonto
2

Answer:

Apples: 30kg. Bananas: 20kg.

Step-by-step explanation:

Let "x" be number of kgs of banana and "2x" be the number of kgs of apple.

Cost of apple  =  1800

Number of kgs of apple (cost per kg)  =  1800

Number of kgs of apple (2x)  =  1800

Number of kgs of apple  =  1800/2x  =  900/x  -----(1)

Number of kgs of banana (cost per kg)  =  600

Number of kgs of banana (x)  =  600

Number of kgs of apple  =  600/x  -----(2)

(1) + (2)

(900/x) + (600/x)  =  50

(1500 / x)  =  50

x  =  1500/50

x  =  30

By applying x = 30 in (1), we get 

  Number of kgs of apple  =  1800/2(30)  =  30

By applying x = 30 in (2), we get 

  Number of kgs of banana  =  600/30  =  20

Answered by abhinayaratnaprabham
3

Answer:

Number of kgs of apple  =  30

Number of kgs of banana  =  20

Step-by-step explanation:

Let "x" be number of kgs of banana and "2x" be the number of kgs of apple.

Cost of apple  =  1800

Number of kgs of apple (cost per kg)  =  1800

Number of kgs of apple (2x)  =  1800

Number of kgs of apple  =  1800/2x  =  900/x  -----(1)

Number of kgs of banana (cost per kg)  =  600

Number of kgs of banana (x)  =  600

Number of kgs of apple  =  600/x  -----(2)

(1) + (2)

(900/x) + (600/x)  =  50

(1500 / x)  =  50

x  =  1500/50

x  =  30

By applying x = 30 in (1), we get

 Number of kgs of apple  =  1800/2(30)  =  30

By applying x = 30 in (2), we get

 Number of kgs of banana  =  600/30  =  20

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