Question

inlet A and B can fill on empty tank completely in 10 hrs and 30 hrs respectively.both the inlets are open simultaneously. there was a leakage in the tank due to which it took 1hr 30mins more to got filled. in how many hours can this leakage empty the full tank​

Answer 1

The ans for . your Q. is 60hrs..✌️

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Answer 2

The water tank will be empty in 45 hours.

Step-by-step explanation:

Given:

Inlet A and B can fill on empty tank completely in 10 hrs and 30 hrs respectively. Both the inlets are open simultaneously.

There was a leakage in the tank due to which it took 1 hr 30 mins more to got filled.

To find:

In how many hours can this leakage empty the full tank

Solution:

Work done by two pipes in an hour = $(\frac{1}{10} + \frac{1}{30}) = \frac{4}{30}$

Time taken to fill the tank = $\frac{30}{4}$ = 7 hrs 30 min.

Due to leakage, time taken = 7 h 30 min + 1 h 30 min = 9 hrs.

Work done by 2 pipes + leak in an hour = $\frac{1}{9}$

Work done leak in an hour = $\frac{4}{30} - \frac{1}{9} = \frac{2}{90} = \frac{1}{45}$

Then, the water tank will be empty in 45 hours.

To know more:

Pipe a can fill a tank in 12 hours. due to a leak at the bottom it takes 20 hours to fill the tank. in what time the leak alone can empty the full tank?

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