Question

inner circle are parallel plate capacitor radius of each plate is 5 cm and their separated by a distance of 2 millimetre calculate the capacitance and the energy stored when it is charged by connecting a battery of 200 volt ​

Answer 1

Answer: The capacitance is $C = 34.7\ pf$ and the stored energy is $E = 6.94\times10^{-7}\ J$.

Explanation:

Given that,

Radius r = 5 cm

Distance d = 2 millimeter

Voltage v = 200 volt

We know that,

The capacitance of the capacitor is

$C = \dfrac{\epsilon_{0}A}{d}$

$C = \dfrac{8.854\times10^{-12}\times3.14\times 0.05\times 0.05}{2\times10^{-3}}$

$C = 34.7\times10^{-12}\ f$

$C = 34.7\ pf$

The stored energy is

$E =\dfrac{1}{2}CV^2$

$E = \dfrac{1}{2}\times34.7\times10^{-12}\times200\times200$

$E = 6.94\times10^{-7}\ J$

Hence, The capacitance is $C = 34.7\ pf$ and the stored energy is $E = 6.94\times10^{-7}\ J$.