Question

Inner circumference of a circular path is 440 m. Width of the path is 14 m. Find
diameter of the outer circle of the circular path.​

Answer 1

Answer:

this is the answer for your question

formulas used:

circumference=2*π*radius

diameter=2*radius

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Answer 2

AnswEr :

• Inner Circumference = 440 m
• Width of Path = 14 m
• Find Diameter of Outer Circle.

⋆ Refrence of Image is in the Diagram :

$\begin{center}\setlength{\unitlength}{1.3 pt}\begin{picture}(100,100)(0,0)\put(0,0){\circle{50}} \put(0,0){\circle{22}} \put(0,0){\circle*{1.5}}\put(-16,0){\line(1,0){31.5}}\put(-15,1.5){\tiny 14 }\end{picture}\setlength{\unitlength}{1 pt}\end{center}$

• According to the Question Now :

$\longrightarrow \tt Inner \:Circumference = 2\pi r \\ \\\longrightarrow \tt440 \:m = 2 \times \dfrac{22}{7} \times r \\ \\\longrightarrow \tt440 \:m = \dfrac{44}{7} \times r \\ \\\longrightarrow \tt \dfrac{ \cancel{440 \:m} \times 7}{ \cancel{44}} = r \\ \\\longrightarrow \tt 10 \:m \times 7 = r \\ \\\longrightarrow \blue{\tt r = 70 \:m}$

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• O U T E R ⠀D I A M E T E R :

⇒ Outer Diameter = 2 × Outer Radius

⇒ Outer Diameter = 2(Inner Radius + Width)

⇒ Outer Diameter = 2 × (70 m + 14 m)

⇒ Outer Diameter = 2 × 84 m

⇒ Outer Diameter = 168 m

⠀

∴ Outer Diameter of Circular Path is 168m

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• S H O R T C U T ⠀T R I C K :

◗ Simply Remember this Table, As whenever Radius will Increase by 3.5, Circumference will increase by 22.

$\begin{tabular}{|c | l|}\cline{1-2}Radius & Circumference \\\cline{1-2}3.5 & 22 \\7 & 44\\10.5 & 66 \\14 & 88\cline{1-2}\cline{1-2}\end{tabular}$

◗ Here Circumference is 440 m, therefore Radius will be 70 m. we put zero because there was zero in Circumference.

• O U T E R ⠀D I A M E T E R :

⇒ Outer Diameter = 2 × Outer Radius

⇒ Outer Diameter = 2(Inner Radius + Width)

⇒ Outer Diameter = 2 × (70 m + 14 m)

⇒ Outer Diameter = 2 × 84 m

⇒ Outer Diameter = 168 m

⠀

∴ Outer Diameter of Circular Path is 168m

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