Inner circumference of a circular path is 440 m. Width of the path is 14 m. Find
diameter of the outer circle of the circular path.
Answers
Answered by
17
★GIVEN :
Circumference of path = 440 cm
Width = 14
★TO FIND :
Outer diameter?
★SOLUTION :
Firstly let's find the radius
\sf \: 440 = 2 \dfrac{22}{7}440=2
7
22
\sf \: 440 = 2 \times \dfrac{22}{7}440=2×
7
22
\sf \: 440 = \dfrac{44}{7}440=
7
44
\sf \: r = \cancel{ 440 \times \dfrac{7}{44}}r=
440×
44
7
\sf \: r = 10 \times 7r=10×7r=10×7r=10×7
Hence :-
Radius = 70 m
\sf \: Outer \: diameter = 2(70 + 14)Outerdiameter=2(70+14)
\sf \: Outer \: diameter = 168 \:Outerdiameter=168
Hence :-
Outer diameter = 168 m.
Answered by
8
Explanation:
Let inner radius be r metres. Then, 2πr = 440 ; r = 440×7/44= 70 m.
Radius of outer circle = (70 + 14) m = 84 m.
Similar questions