Question

inner circumference of a circular path is 44om. width of the path is 14m find diameter of the outer circle of the circular path.​

Answer 1

Given -

• Inner Circumference = 440 m

• Width of Path = 14 m

To find -

• Find Diameter of Outer Circle.

Solution -

Circumference of circle = 2πr

Where,

π = 22/7

r = radius

Let the radius be termed as 'r'

On substituting the values -

Circumference of inner circle = 2πr

→ 440 =2 × 22/7 × r

→ 440 = 44/7 × r

→ r = 440 × 7/44

→ r = 7 × 10

→ r = 70m

Now for outer diameter -

→ Outer diameter = 2 × inner radius + width given

→ Outer diameter = 2 × (70 + 14)

→ Outer diameter = 2 × 84m

→ Outer diameter = 168m

$\therefore$ Radius = 70m and outer diameter = 168m

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Answer 2

Answer:

Given :-

• Circumference of path = 440 cm
• Width = 14

To Find :-

Outer diameter

Solution :-

Firstly let's find the radius

$\sf \: 440 = 2 \dfrac{22}{7} r$

$\sf \: 440 = 2 \times \dfrac{22}{7} \times r$

$\sf \: 440 = \dfrac{44}{7} r$

$\sf \: r = \cancel{ 440 \times \dfrac{7}{44} }$

$\sf \: r = 10 \times 7$

Hence :-

Radius = 70 m

Outer diameter

$\sf \: outer \: diameter = 2(70 + 14)$

$\sf \: outer \: diameter = 168 \: m$

Hence :-

Outer diameter = 168 m.