Question

Inner circumference of a circular path is 44om. width of the path is 14m find diameter of the outer circle of the circular path.​

Answer 1

★GIVEN :

Circumference of path = 440 cm

Width = 14

★TO FIND :

Outer diameter?

★SOLUTION :

Firstly let's find the radius

$\sf \: 440 = 2 \dfrac{22}{7}$

$\sf \: 440 = 2 \times \dfrac{22}{7}$

$\sf \: 440 = \dfrac{44}{7}$

$\sf \: r = \cancel{ 440 \times \dfrac{7}{44}}$

$\sf \: r = 10 \times 7r=10×7$

Hence :-

Radius = 70 m

$\sf \: Outer \: diameter = 2(70 + 14)$

$\sf \: Outer \: diameter = 168 \:$

Hence :-

Outer diameter = 168 m.

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Answer 2

Answer:

Inner circumference =2πr=2×7

22

×r=

7

44r

Given

7

44r

=440⇒r=

44

440×7

=70 m

∴ Radius of outer circle =70 m+14 m=84 m

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