inner circumference of a circular track is 528 m and width of the track is 9 metre. find the radius of the outer track
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Answer:
Outer circumference=528m
=2πr=528m⇒⇒R=
44
528×7
=84m
Width of track=14m
Inner radius, r=84−14=70m
∴Area of trackπ(R
2
−r
2
)=
7
22
(84
2
−70
2
)
=
7
22×2156
=6776m
2
Cost of leveling=Rs.(6776×0.50)=Rs. 3388
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