Math, asked by harsh179, 1 year ago

inner dimension of an open wooden box are 65cm*45cm*30cm and it is made of 2.5cm thick wood. find the capital of the box. also find the weight of the box in kg if 60 cu cm wood weighs 9 grams.

Answers

Answered by AkashMandal
12
solution :-

here, Given : Length = 65 cm, Breadth = 45 cm, Height = 30 cm

Now, the capacity of the box will be equal to the inner volume of the box.
( length × breadth × height)

Hence, the inner volume(capacity) = (65 ×45 × 30) cm3 = 87750 cm3

Now ,it has been also given that the thickness of wood is 2.5 cm
Hence, the outer length will be 65+(2.5 + 2.5) = 70 ........(since the thickness is from both sides of inner length)

Similarly, the outer breadth will be 45+(2.5 +2.5) = 50 cm
& the outer height will be 30+(2.5 +2.5) = 35 cm

Hence, the outer volume of the box will be = (70 × 50 ×35) cm3 = 122500 cm3

Hence, the volume of block used = (122500 - 87750)cm3 = 34750 cm3

Now, 60cm3 of wood weighs = 9 gms
1cm3 of wood weighs = 9/60
114700cm3 of wood weighs =(9×34750) /60 = 5212.5 gms or 5.2125 kgs

So, the inner capacity of box is 87750 cm3 and the weight of box is 5.2125 kgs
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