Question

Input a number and find the sum of its digits. Input – 346 Output - 13

Answer 1

${\boxed{\underline{\purple{\bf\tt{Program:} } }}}$

n=int(input("Enter a number:"))

sum=0

#Program by Ankitraj707

while(n>0):

$\: \: \: \:$ dig=n%10

$\: \: \: \:$ sum=sum+dig

$\: \: \: \:$ n=n//10

print("The total sum of digits is:",sum)

${\boxed{\underline{\green{\bf\tt{Explanation:} } }}}$

We are using while loop here.

We have assigned a variable sum=0 outside the while loop.

Under the while loop having condition n>0

We have dig=n%10 which will give the remainder or the last digit of a number.

Take an example of 123

Divide it by 10, what will be the remainder

123%10=3

Now,we have sum= sum +dig = 0+3=3

and we have n=n//10, here the value of n keeps changing until n=0

n= 123//10= 12

And now this value of n will go to dig=n%10= 12%10=2

And this get stored in sum.

And at last sum of 123 will be Printed.

${\boxed{\underline{\orange{\bf\tt{Output :} } }}}$

Enter a number: 123

The total sum of digits is 6