Question

input a string and find the sum of all digits present in it​

Answer 1

Answer:

void main()

{

   char string[80];

   int count, nc = 0, sum = 0;

 

   printf("Enter the string containing both digits and alphabet \n");

   scanf("%s", string);

   for (count = 0; string[count] != '\0'; count++)

   {

       if ((string[count] >= '0') && (string[count] <= '9'))

       {

           nc += 1;

           sum += (string[count] - '0');

       }

   }

   printf("NO. of Digits in the string = %d\n", nc);

   printf("Sum of all digits = %d\n", sum);

}

Explanation:

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