input marks of a student. If marks are >or= to 85 then display "good performance" else display "More effert required
Answers
Answered by
3
Answer:
#Approach 1:-
marks=(int)(input("Enter your marks:))
print("Good Performance" if (marks>=80) else "More effort required")
#Approach 2(one-liner):-
print("Good Performance" if (int(input("Enter your marks:"))>=80) else "More effort required")
Logic:-
- Accept marks as input and check if it is greater than 80 or not
- if yes, display "Good Performance"
- otherwise, display "More effort required"
Required Output Attached.
Attachments:
Answered by
2
Python::
marks = int(input())
print("Marks entered by you :-- " + str(marks)
if marks >= 85:
print("good performance")
else:
print("More effort required")
Output::
==> Asks you for input and outputs according to the instructions.
Hope It Helps You..♪
Similar questions