Inradius of a right triangle with hypotenuse 17cm is 3cm. What is the area of the triangle?
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Step-by-step explanation:
Given Inradius of a right triangle with hypotenuse 17cm is 3cm. What is the area of the triangle?
- We need to find the area of the triangle
- So given hypotenuse = 17 cm, radius r = 3 cm
- Now Inradius of a right angled triangle is given by r = (P + B – H) / 2
- So 3 = (P + B – 17) / 2
- Or P + B – 17 = 6
- Or P + B = 23
- Squaring both sides we get
- P^2 + B^2 + 2 PB = 529
- So P^2 + B^2 = h^2
- Or h^2 + 2 PB = 529
- 17^2 + 2PB = 529
- 2 PB = 529 – 289
- 2 PB = 240
- Or PB = 120
Therefore Area of the circle will be 120 sq cm
Reference link will be
https://brainly.in/question/2263632
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