Question

ins. 2
A car starts from rest and moves with a
uniform acceleration of 2 m/s2. How much
time will it take to cover the distance of 49 m?​

Answer 1

Since the car starts from rest

So

u ( Initial velocity ) = 0 m/s

Given

a ( acceleration ) = 2 m/s^2

s ( distance covered ) = 49 m

t ( time taken ) = ?

By 2nd equation of motion, we have

$s = ut + \frac{1}{2} a {t}^{2}$

$49 = 0 \times t + \frac{1}{2} 2 {t}^{2}$

$49 = 0 + {t}^{2}$

$49 = {t}^{2}$

$\sqrt{49} = t$

$7 = t$

Thus required time taken is 7 second

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