inser A.M.s between 7 and 71 in such a way that the 5th A.M. is 27. find the number of A.M.s.
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Here , a=7 , c=71
5th A.M. is = 27
a+5d=27 [ d= common difference]
7+5d=27
5d=20
d=4
Now we have, d=(c-a)/(n+1)
4=(71-7)/(n+1)
4(n+1)=64
4n =60
n=15
Therefor number of A.M. is 15
5th A.M. is = 27
a+5d=27 [ d= common difference]
7+5d=27
5d=20
d=4
Now we have, d=(c-a)/(n+1)
4=(71-7)/(n+1)
4(n+1)=64
4n =60
n=15
Therefor number of A.M. is 15
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