Question

insert 3 A.M's between -18 and 4 show that their sum is 3 times the single A.M. between -18 and 4.<br />

Answer 1

let AM s be a+d,a+2d,a+3d
than a=-18
a+4d=4
-18+4d=4
d=22/4
than a+d=-18+22/4=-50/4
and a+2d=-18+2*22/4=-28/4
and a+3d=-18+3*22/4=-6/4
and their sum is -50/4+(-28/4)+(-6/4)= -21
and if their is a single am b/w -18 and 4 than it would be (-18+4)/2=-7
whose three times is =-21
hope it helps u

Answer 2

Answer:

I hope it is helpful for us