insert 3 numbers between 1 and 256 so that the resulting sequence in geometrical progression
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17
First term is 1
you need to I insert 3 terms in between
so 256 becomes the 5th term
and the answer is as follows
you need to I insert 3 terms in between
so 256 becomes the 5th term
and the answer is as follows
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Answered by
27
Dear Student,
● Answer -
4, 16 and 64
◆ Explanation -
If we insert 3 terms between 1 and 256, it will be GP with 1 being t1 and 257 being 256.
t1 = a = 1
t2 = ar
t3 = ar^2
t4 = ar^3
t5 = ar^4 = 256
Dividing t5 by t1,
ar^4 / a = 256 / 1
r^4 = 256
r = 4
Now,
t2 = ar = 1×4 = 4
t3 = ar^2 = 1×4^2 = 16
t4 = ar^3 = 1×4^3 = 64
So, three numbers to be inserted are 4, 16 and 64.
Hope this helps you...
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