Question

Insert 3A.M's b/w 3 and 15​

Answer 1

Here 3 is first term and 19 is second term. If you insert 3 arithmatic means between them, 19 will become 5th term of Arithmatic Progression.

T(n) = first term + (n-1)d. Where T(n) is n th term and d is the common difference of an Arithmatic Progression.

T(5) = T(1) + (5–1)d

19 = 3 + 4d

This gives d = 4

There the sequence becomes

3, 3+4, 3+2*4, 3+3*4,19

3, 7, 11, 15, 19…..

Answer 2

Answer:

hope it helps you.... .