Question

insert 4 AM's. between 9 and 29

Answer 1

let 4 AM be  a2 ,a3 ,a4 ,a5th  term of AP  

where 29 is 6th term

29=a1+5d⇒29=4+5d⇒d=$\frac{25}{5}$

d=5  

there fore 4 AM are 9,14,19,24