Question

insert 4 Arithmetic mean between 5 and 20

Answer 1

According to question
A=5
A+5d=20
5d=15
D=3
First AM=a+d=8
2AM=5+6=11
3AM=5+9=14
4AM=5+12=17

Answer 2

Answer:

8, 11, 14, 17

Step-by-step explanation:

a=5, l(last term)=20

also we need to insert 4 AMs and 2 terms are already given hence n=6

last term= a+(n-1)d=20

5+5d=20

d=3

so 1st AM= a+d=8

2nd AM = a+2d= 11

3rd AM= a+3d = 14

4th AM= a+4d= 17.