Question

insert 4am between 11 and -1​

Answer 1

Answer:

After inserting 4 arithmetic means between 3 and 23 you will have 5 (five) intervals of equal lengths,  

that together comprise the interval of the total length of  23-3 = 20 units.

So, each elementary interval is  20%2F5 = 4  units long.

Hence, the A.M. to be inserted are  

•   3  +  4 =  7,
•    7 +  4 = 11,
•   11 +  4 = 15,
•  15 +  4 = 19.

Step-by-step explanation:

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