insert 5 geometric means between 4/5 and 5/6.
Answers
Answered by
1
Answer:
Let a1 , a2 , a3 , a4 , a5 be 5 gepmetric means between a = 576 and b = 9
So, the sequence a, a1 , a2 , a3 , a4 , a5 , b is in GP
Now, common ratio r = (b/a)1/(n + 1)
=> r = (9/576)1/(5 + 1)
=> r = (1/64)1/6
=> r = (1/26 )1/6
=> r = 1/2
Now, a1 = ar = 576 * (1/2) = 576/2 = 288
a2 = ar2 = 576 * (1/2)2 = 576/4 = 144
a3 = ar3 = 576 * (1/2)3 = 576/8 = 72
a4 = ar4 = 576 * (1/2)4 = 576/16 = 36
a5 = ar5 = 576 * (1/2)5 = 576/32 = 18
So, 288, 144, 72, 36, 18 are the 5 geometric means inserted between 576 and 9
Similar questions