Question

Insert 5 rational numbers between :
(¡) -3/11 and -1/13
(¡¡) 3/8 and -1/2
(¡¡¡) 2/3 and 3/13

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Concept Introduction:-

It could take the shape of a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that $(i) -3/11$ and $-1/13$, $(ii)3/8$ and $-1/2$, $(iii)2/3$and $3/13$

To Find:-

We have to find that insert $5$ rational numbers between

Solution:-

According to the problem

$(i) -3/11$ and $-1/13$ are two rational number

L.C.M of $(11,13)=143$

$\frac{-3}{11}= \frac{-3\times 13}{11\times 13}=\frac{-39}{143}\\\frac{-1}{11}= \frac{-1\times 11}{13\times 11}=\frac{-11}{143}$

$5$ rational numbers between $\frac{-39}{143}$and $\frac{-11}{143}$ are $\frac{-38}{143},\frac{-37}{143},\frac{-36}{143},\frac{-35}{143}\frac{-34}{143}$.

$(ii)3/8$ and $-1/2$ are two rational number

L.C.M of $(8,2)=8$

$\frac{3}{8}= \frac{3\times 1}{8\times 1}=\frac{3}{8}\\\frac{-1}{2}= \frac{-1\times 4}{2\times 4}=\frac{-4}{8}$

$5$ rational numbers between $\frac{3}{8}$and $\frac{-4}{8}$ are $\frac{-3}{8}, \frac{-2}{8},\frac{-1}{8},\frac{1}{8},\frac{2}{8}$

$(iii)2/3$and $3/13$ are two rational number

L.C.M of $(3,13)=39$

$\frac{2}{3}= \frac{2\times13}{3\times13}=\frac{26}{39}\\\frac{3}{13}= \frac{3\times3}{13\times3}=\frac{9}{39}$

$5$ rational numbers between $\frac{9}{39}$and $\frac{26}{39}$ are $\frac{10}{39}, \frac{11}{39},\frac{12}{39},\frac{13}{39},\frac{14}{39}$

Final Answer:-

The correct answer are $\frac{-38}{143},\frac{-37}{143},\frac{-36}{143},\frac{-35}{143}\frac{-34}{143}$ and  $\frac{-3}{8}, \frac{-2}{8},\frac{-1}{8},\frac{1}{8},\frac{2}{8}$ and $\frac{10}{39}, \frac{11}{39},\frac{12}{39},\frac{13}{39},\frac{14}{39}$.

#SPJ2