insert 6 numbers between 8 and 26 that the result sequence is an automatic progression
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Step-by-step explanation:
Let a
1
,a
2
,a
3
,a
4
,a
5
be five natural numbers between 8 and 26
Such that 8,a
1
,a
2
,a
3
,a
4
,a
5
,26 is an A.P.
Let d be the common difference.
Then,
d=
5+1
26−8
=3 [∵d=
n+1
b−a
]
∴a
1
=8+3=11,a
2
=a
1
+3=14,a
3
=17,a
4
=20 and a
4
=23
Hence, five numbers are 11,14,17,20 and 23.
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