Math, asked by apple6924, 8 months ago

Insert 6 rational numbers between 3/2&5/4

Answers

Answered by NailTheArtist2

2

Required number = 1/2 (2/7 + 3/4)

= 1/2 ((8 + 21)/28)

= {1/2 × 29/28)

= 29/56

Hence, 29/56 is a rational number lying halfway between 2/7 and 3/4.

Answered by HariesRam

3

Answer:

Rational numbers between 3/2 & 5/4

LCM of 2 and 4 = 4

3/2 × 2/2 = 6/4

5/4 × 1/1 = 5/4

The required 6 rational numbers will be

5.9/4, 5.7/4, 5.6/4, 5.5/4, 5.3/4, 5.1/4.

Previous Question

Next Question

Similar questions

Math, 4 months ago

Find the length of the side of a square whose area is 441 metre square...

Physics, 4 months ago

johny goes to school 500m away in two ways.he travel half the distance by bus with a speed of 40 m/s. the remaining half distance by walking with a speed 10 m/s.calculate the average speed during the complete journey.

History, 4 months ago

The policies of the East india Company affected different people in different ways. the nawabs and rajas started losing their authority and their revenue and territories were gradually taken away. What was the next step in the Company's plan to colonise India? plzz answer fast guys :(...

Math, 8 months ago

question 8 please solve it please ...

Economy, 8 months ago

advantages and disadvantages of boon and bane for the farmer...

Math, 11 months ago

For $x\epsilon\left(0, \frac{5\pi}{2}\right)$ , define $f(x)=\int\limits^x_0 {\sqrt{t}\sin t}\, \ dt$ . Then f has (a) local minimum at π and 2π (b) local minimum at π and local maximum at 2π (c) local maximum at π and local minimum at 2π (d) local maximum at π and 2π...

Math, 11 months ago

Angle between the tangents to the curve y = x² - 5x + 6 at the points (2, 0) and (3, 0) is(a) π(b) $\frac{\pi}{2}$ (c) $\frac{\pi}{6}$ (d) $\frac{\pi}{4}$ ...

Math, 11 months ago

Let k and K be the minimum and the maximum values of the function f(x) = $\frac{(1+x)^{0.6}}{1+x^{0.6}}$ in [0, 1] respectively, then the ordered pair (k, K) is equal to: (a) $(2^{-0.4}, 1)$ (b) $(2^{-0.4}, 2^{0.6})$ (c) $(2^{-0.6}, 1)$ (d) $(1, 2^{0.6})$ ...