Math, asked by ginjalasripal, 7 hours ago

Insert 8 AM BETWEEN - 5 and 13​

Answers

Answered by amitnrw
2

Given :  - 5 and 13​

To Find : Insert 8 AM BETWEEN - 5 and 13​

Solution:

Inserting n AM between a  and b

are :

a + (1* (b - a) / (n + 1)) , a  + (2* (b - a) / (n + 1)) _____a  + (n-1)(2* (b - a) / (n + 1))

8 AM between -5  and 13

-5 +  1 * (13 - (-5))/(8 + 1)  = - 3

-5 +  2 * (13 - (-5))/(8 + 1)  = - 1

-5 +  3 * (13 - (-5))/(8 + 1)  =  1

-5 +  4 * (13 - (-5))/(8 + 1)  =  3

-5 +  5 * (13 - (-5))/(8 + 1)  =  5

-5 +  6 * (13 - (-5))/(8 + 1)  =  7

-5 +  7 * (13 - (-5))/(8 + 1)  =  9

-5 +  8 * (13 - (-5))/(8 + 1)  =  11

-3 , - 1 , 1 , 3 , 5 , 7 , 9 and 11 are 8 AM

Another method :

Let sat 8 AM inserted between - 5 and 13​

then this will be an AP of 8 + 2 =  10 terms

where -5  is first term  a, 13 is last term

Hence using aₙ = a + ( n - 1) d

=> 13 = -5 + (10 - 1) d  => d = 2

so AM will be

-5 + 2  , - 5 + 2 * 2 , -5 + 3 * 2, _____________________-5 + 8*2

-3 , - 1 , 1 , 3 , 5 , 7 , 9

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