Question

insert an airthmetic mean between (p-q) and (p+q).

Answer 1

Hey there!

n Arithmetic means between a, b are required then, d = b - a / n + 1 .

Here, We require only one arithmetic mean so denominator will be 2 .

d = ( p + q) - ( p - q) / 2

= ( p + q - p + q) / 2

= 2q/2

= q.

Therefore, Arithmetic mean a +d = p - q + q = p.

This can be found in other methods :

Arithmetic mean between (p-q) and (p+q).

$= \frac{(p + q) + (p - q)}{2} \\ \\ = \frac{2p}{2} \\ \\ = p$

$\boxed{\begin{minipage} {20em} \textbf{ therefore , Arithmetic mean between } \\ \textbf{ (p-q) and (p+q) is p } \end{minipage}}$

Answer 2

Answer:

hope it's help full to you

Step-by-step explanation:

formula for airthmetic mean of an A.P. = a + b /2. here a = p-q ,and b = p+q. =( p -q +p+q) / 2.