Math, asked by ashish127, 1 year ago

insert four arithmetic mean between 3 and 18

Answers

Answered by siddhartharao77

Given a0 = 3 and an=18.

We know that an = a0 + n * d

18 = 3 + 5d

d = 3.

a1 = 3 + 3 = 6

a2 = 6 + 3 = 9

a3 = 9 + 3 = 12

a4 = 12 + 3 = 15.

Answered by Laxmipriyas007

Answer:

Four arithmetic means between 3 and 18 are 6, 9, 12, 15.

Step-by-step explanation:

To find:

To find four arithmetic means between 3 and 18.

Formula used:

In arithmetic progression, the nth term is given by

a + ( n - 1 ) d,

Where,

a= first term of AP

d = Common difference

Let x, y, z, and s be four means between 3 and 18.

Then 3, x, y, z, s, 18 are in arithmetic progression.

First term = a = 3.

Common difference:

x = 3 + d,..........................( 1 )

y = 3 + 2d,.......................( 2 )

z = 3 + 3d........................( 3 )

s = 3 + 4d,.......................( 4 )

18 = 3 + 5d

5d = 18 - 3,

5d = 15,

=> d = 15 / 5,

=> d = 3.

Substitute the value of d in equations ( 1 ), ( 2 ), ( 3 ), ( 4 ), and we get

( 1 ) => x = 3 + 3 = 6.

( 2 ) => y = 3 + 2(3) = 3 + 6 = 9.

( 3 ) => z = 3 + 3(3) = 3 + 9 = 12.

( 4 ) => s = 3 + 4 (3) = 3 + 12 = 15.

Therefore, four arithmetic means between 3 and 18 are 6, 9, 12, and 15.