insert four irrational numbers between 3root3 and 4root2
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Answer:
√28, √29, √30, √31
Step-by-step explanation:
Consider the squares of 3√3 and 4√2.
(3√3)^2 = 9×3=27 and (4√2)^2 = 16×2=32
As 27<28<29<30<31<32, it follows that
√27 < √28 < √29 < √30 < √31 < √32, therefore
√28, √29, √30, √31 lie between √27 and √32 i.e between 3√3 and 4√2.
Hence, four irrational numbers between 3√3 and 4√2 are √28, √29, √30, and √31
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