Math, asked by yuvrajrathore, 1 year ago

insert four irrational numbers between 3root3 and 4root2​

Answers

Answered by aarushigupta23
0

I can't understand your question please write ones more

Answered by reynarachelthomas20
1

Answer:

√28, √29, √30, √31

Step-by-step explanation:

Consider the squares of 3√3 and 4√2.

(3√3)^2 = 9×3=27 and (4√2)^2 = 16×2=32

As 27<28<29<30<31<32, it follows that

√27 < √28 < √29 < √30 < √31 < √32, therefore

√28, √29, √30, √31 lie between √27 and √32 i.e between 3√3 and 4√2.

Hence, four irrational numbers between 3√3 and 4√2 are √28, √29, √30, and √31

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