Question

Insert four Numbers between 8 and 26 so that the resulting sequence is an A.P
(11th class Maths)

Answer 1

27-7=18
So 18 is divided 6 parts
So difrence is 3
11,14,17,21,

Answer 2

As we have to find an AP of 6 terms having first and last term as 8 and 26.
Firstly, we will find common difference.
So, We know An = A+(n-1)d
Here, 26= 8+(6-1)d = 8+5d
5d = 26-8 = 18
d=18/5.
So, The sequence will be
8,8+18/5 ,8+2*18/5,8+3*18/5,8+4*18/5 ,26
i.e.8,58/5, 76/5,94/5,112/5,26 .