Question

Insert one rational number between 2/9 and 3/8 and arrange in descending order

Answer 1

Answer:

In descending order 27/72 > 21/72 > 16/72

Step-by-step explanation:

2×8/9×8 = 16/72,

3×9/8×9 = 27/72

then,

16/72 < 21/72 < 27/72

And in descending order , that is given above

Answer 2

$\large\sf\underline\pink{† Given:}$

• Two rational numbers 2/9 and 3/8

$\large\sf\underline\blue{† To \:do:-}$

• Insert one rational number between 2/9 and 3/8
• And, Arrange them in descending order.

$\large\sf\purple{†Solution:-}$

Since, the given rational numbers have different denominators , we first need to make the denominators same!

L.C.M of 9 and 8 = 72 ;

$\bf{ \frac{2}{9} = \frac{2 \times 8}{9 \times 8} = \frac{16}{72} }$

$\bf{ \frac{3}{8} = \frac{3 \times 9}{8 \times 9} = \frac{27}{72} }$

Since 16 < 27

$\bf{ \frac{16}{72} < \frac{27}{72} }$

so,

$\bf{ \frac{2}{9} < \frac{5}{8} }$

Now, A rational number between them is :-

$\implies\bf{ \frac{ \frac{2}{9} + \frac{3}{8} }{2} }$

$\implies \bf\frac{2 \times 8 + 3 \times 9} { \frac{72}{2}}$

$\implies \bf\frac{16+ 27}{72 \times 2}$

$\implies \bf \frac{43}{144}$

Now, by arranging the rational numbers in descending order we get,

$\bf \green { \frac{3}{8} , \frac{43}{144} , \frac{2}{9} }$

Hope it helps uh :)