Math, asked by harshitamall42, 6 months ago

Insert single arithmetic mean between 8 and 26​

Answers

Answered by nightsky275
3

Answer:

17

Step-by-step explanation:

Single AM between 2 No.s a & b is given by

(a+b)/2

Single AM between 8 & 26

= (8+26)/2 = 34/2 = 17

Answered by steffiaspinno
0

17

It is the simple average or sum of a series of integers divided by the total count of those numbers.

A represents the arithmetic mean of numbers 'a' and 'b'.

As they are in A.P.,

the difference between those will be constant

   A - a = d and

   b - A = d

Therefore, A - a = b - A

            2A = a + b

                         A = \frac{a+b}{2}  

Thus the required arithmetic mean (A.M) of two numbers 'a' and 'b' is  

\frac{a+b}{2}

       Given that, a= 8

                          b= 26

Arithmetic mean=

                           = \frac{34}{2}

                           = 17

Single arithmetic mean between 8 and 26 is 17.

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