Question

Insert six numbers between 23 and 9 so that all eight numbers are in arithmetic sequence.

Plz do the step by step explanation

Answer 1

Answer:

like my answer

follow me

Step-by-step explanation:

Let a

1

,a

2

,a

3

,a

4

,a

5

be five natural numbers between 8 and 26

Such that 8,a

1

,a

2

,a

3

,a

4

,a

5

,26 is an A.P.

Let d be the common difference.

Then,

d=

5+1

26−8

=3 [∵d=

n+1

b−a

]

∴a

1

=8+3=11,a

2

=a

1

+3=14,a

3

=17,a

4

=20 and a

4

=23

Hence, five numbers are 11,14,17,20 and 23

Answer 2

its the answer..........