insert the 1 geometric mean of 1/3 and 64/3
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Answer:
An=A1(r)^[n-1]
A3= A1(r)[3-1]
64/3= 1/3(r)^2
64=r^2
\sqrt[64] = \sqrt[r^2]
r = 8
To get the Geometric Mean/2nd term. Use formula.
A2=A1(r)
A2= 1/3(8)
A2= 8/3
The Geometric Sequence would be 1/3, 8/3 , 64/3
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