Question

insert three A.M's between-18 and 4​

Answer 1

Answer:

let AM s be a+d,a+2d,a+3d

than a=-18

a+4d=4

-18+4d=4

d=22/4

than a+d=-18+22/4=-50/4

and a+2d=-18+2*22/4=-28/4

and a+3d=-18+3*22/4=-6/4

and their sum is -50/4+(-28/4)+(-6/4)= -21

and if their is a single am b/w -18 and 4 than it would be (-18+4)/2=-7

whose three times is =-21

hope it helps u