Math, asked by aritranandi15, 11 months ago

insert three arithmetic means between - 5 and 7

Answers

Answered by swethassynergy
3

Three arithmetic means between - 5 and 7 are -2, 1 and 4 .

Step-by-step explanation:

Given:

5 and 7.

To Find:

Three arithmetic means between - 5 and 7.

Formula Used:

nth term of the Arithmetic Progression (A.P) tn= a+(n-1)d  -- formula no.01.

Where

a = first term

d =   common difference.

n =  number of the  terms

tn =  nth term of the Arithmetic Progression (A.P)

Solution:

As given, -5 and 7.

Let Three arithmetic means are A,B and C which are inserted between -5 and 7.

The resulting  sequence will be Arithmetic Progression (A.P.) with  first term a and common difference d,

-5,A,B,C,7

First term a=-5

5^{th} term = 7

Applying the formula no.01.

(-5)+(5-1)d=7

-5+4d=7

4d=12

d=3

First arithmetic mean,A =a+d\\

                                       =-5+3= -2

Second arithmetic mean,B =a+2d\\

                                             =-5+2\times3= 1

Third arithmetic mean,C=a+3d\\

                                         =-5+3\times3= 4

Thus,three arithmetic means between - 5 and 7 are -2, 1 and 4 .

#SPJ3

Answered by gayatrikumari99sl
0

Answer:

-2, 1 and 4 are the required three arithmetic means between -5 and 7.

Step-by-step explanation:

Explanation:

Give two numbers -5 and 7.

  • As we know, arithmetic means two numbers a and is \frac{a + b}{2}.

Let A_1 , A_2  and A_3 are the three arithmetic means between -5 and 7.

So,  -5,A_1 , A_2 ,A_3, 7  are in A.P.

  • As we know, A_1 , A_ 2, A_3 ...........A_n are n arithmetic between a and b where d = \frac{b - a}{n + 1}.

Step 1:

We have,   -5,A_1 , A_2 ,A_3, 7

a = -5 and b = 7 and n = 3

Now, first, we find out the value of d which stands for the common difference.

⇒ d = \frac{b - a}{n + 1}

⇒ d = \frac{7 - -5}{3 + 1}

⇒ d = \frac{12}{4} = 3

Step 2:

As we have, A _1 , A_2 and A_3 are the required three arithmetic means.

A_ 1 = a + d

A_ 1 = -5 + 3 = -2

A_2 = a + 2d

A_2 = -5 + 2 (3) = -5 + 6 = 1

And A_3 = a + 3d

A_ 3 = -5 + 3 (3) = -5 + 9 = 4

Final answer:

Hence, -2, 1 and 4 are the required three arithmetic means between -5 and 7.

#SPJ3

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