Question

insert three arthematic means between 4 and 7

Answer 1

First term = 4
Last term = 7

We need to find 3 A. M's so, n = 3 .

Common difference d = b - a / n + 1 = 7 - 4 / 3 + 1 = 3/4

Now,
The three A.M's are
1) 4 + 3/4 = 19/4
2) 4 + 6/4 = 22/4
3) 4 + 9/4 = 25/4 .

The required 3 A.M ' s are 19/4 , 22/4 , 25/4