Question

Insert three Geometrical Mean between 1/6 and 216

Answer 1

Answer:

Firstly we find the

Common Ratio (r) =

${ (\frac{b}{a} )}^{ \frac{1}{n + 1} }$

Therefore..

r = ${ \frac{216}{ \frac{1}{6} } }^{ \frac{1}{3 + 1} }$

r = $( {216 \times 6})^{ \frac{1}{4} }$

So ... r = 6

Hence the geometric means are

$ar = \frac{1}{6} \times 6 = 1$

$a {r}^{2} = \frac{1}{6} \times 6 \times 6 = 6$

$a {r}^{3} = \frac{1}{6} \times 6 \times 6 \times 6 = 36$

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Answer 2

Answer:

Let G

1

,G

2

,G

3

be 3

GMS both 1, & 256

then

1,G

1

,G

2

,G

3

, 256 will be in GP

Let common ratio be r

∴G

1

=r

So r

4

=256

r=±4

G

1

=±4

G

2

=±16

G

3

=±64

Step-by-step explanation:

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