insert three rational numbers between 3/5 and 2/3
Answers
Answered by
518
Hello Mate!
Rational umber inserting = ( r + s ) / 2
= ( 3/5 + 2/3 ) ÷ 2
= ( 9 + 10 ) / 15 ÷ 2
= 19/15 × 1/2
= 19/30
In 3/5 and 19/30
= ( 3/5 + 19/30 ) ÷ 2
= 37/30 × 1/2
= 37/60
In 19/30 and 2/3
= ( 19/30 + 2/3 ) ÷ 2
= 39/30 × 1/2
= 39/60
3/5 < 37/60 < 19/30 < 39/60 < 2/3
Hope it helps☺!✌
Rational umber inserting = ( r + s ) / 2
= ( 3/5 + 2/3 ) ÷ 2
= ( 9 + 10 ) / 15 ÷ 2
= 19/15 × 1/2
= 19/30
In 3/5 and 19/30
= ( 3/5 + 19/30 ) ÷ 2
= 37/30 × 1/2
= 37/60
In 19/30 and 2/3
= ( 19/30 + 2/3 ) ÷ 2
= 39/30 × 1/2
= 39/60
3/5 < 37/60 < 19/30 < 39/60 < 2/3
Hope it helps☺!✌
Answered by
383
Hi ,
a ) 3/5 = ( 3 × 3 ) / ( 5 × 3 ) = 9/15
= 18/30 = 36/60
b ) 2/3 = ( 2 × 5 ) / ( 3 × 5 ) = 10/15
= 20/30 = 40/60
[ 3/5 = 36/60 ] < 37/60< 38/60<39/60< [ 40/60 = 2/3 ]
Therefore ,
Required 3 numbers are ,
37/60 , 38/60 , 39/60
I hope this helps you.
: )
a ) 3/5 = ( 3 × 3 ) / ( 5 × 3 ) = 9/15
= 18/30 = 36/60
b ) 2/3 = ( 2 × 5 ) / ( 3 × 5 ) = 10/15
= 20/30 = 40/60
[ 3/5 = 36/60 ] < 37/60< 38/60<39/60< [ 40/60 = 2/3 ]
Therefore ,
Required 3 numbers are ,
37/60 , 38/60 , 39/60
I hope this helps you.
: )
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