Question

insert three rational numbers between the following number 3/8 and 7/12 ps fastely​

Answer 1

☯GIVEN :

• $\bf{ \dfrac{3}{8}}$ and $\bf{ \dfrac{7}{12} }$

☯TO FIND :

• Three rational numbers between $\bf{ \dfrac{3}{8}}$ and $\bf{ \dfrac{7}{12} }$.

☯KNOWLEDGE REQUIRED :

• Rational numbers can be found between two rational numbers (x and y), when x is less than y (x< y).

☯FORMULA REQUIRED :

• $\bigstar \underline{ \purple{\boxed{ \bf{ Rational \: Number = \dfrac{x+ y}{2} }}}}$

➲SOLUTION :

• 1)

$\implies{ \sf{ Rational \: Number =\dfrac{x + y}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac{\dfrac{3}{8} + \dfrac{7}{12}}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{9+ 14}{24}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{23}{24}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac{23}{24} \div 2 }}$

$\implies{ \sf{ Rational \: Number = \dfrac{23}{24} \times \dfrac{1}{2} }}$

$\implies{ \boxed{ \pink{ \bf{ Rational \: Number = \dfrac{23}{48} }}}}$

• 2)

$\implies{ \sf{ Rational \: Number =\dfrac{x + y}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac{\dfrac{3}{8} + \dfrac{23}{48}}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{18+ 23}{48}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{41}{48}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac{41}{48} \div 2 }}$

$\implies{ \sf{ Rational \: Number = \dfrac{41}{48} \times \dfrac{1}{2} }}$

$\implies{ \boxed{ \green { \bf{ Rational \: Number = \dfrac{41}{96} }}}}$

• 3)

$\implies{ \sf{ Rational \: Number =\dfrac{x + y}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac{\dfrac{23}{48} + \dfrac{7}{12}}{2} }}$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{23 + 28}{48}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac { \dfrac{51}{48}}{2}} }$

$\implies{ \sf{ Rational \: Number = \dfrac{51}{48} \div 2 }}$

$\implies{ \sf{ Rational \: Number = \dfrac{\cancel {51}}{\cancel{48}} \times \dfrac{1}{2}}}$

$\implies{ \boxed{ \blue{ \bf{ Rational \: Number = \dfrac{17}{32} }}}}$