inside of a cube is increased by 50% then what percent increase in its surface area
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let side of cube is a
surface area of cube S = 6a^2
so new side of the cube = a + a × 50%
= a + 50a/2 = a + a/2 = 3a/2
new surface area of cube
= 6× (new side)^2
= 6 × (3a/2)^2
= 6 × 9a^2 / 4
=( 27/2 )× a ^2
increased % = (new SA - old SA) × 100/(old SA)
=( ( 27/2 )× a ^2 - 6a ^2) × 100/ (6a^2)
= (27/2 - 6) × a^2 × 100/ (6a^2)
= 15/2 × 100 /6
= (15×100)/(2×6)
= 125 %
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