Question

inside of a cube is increased by 50% then what percent increase in its surface area​

Answer 1

Answer:

125% Increase in surface area.

Step-by-step explanation:

Assume the initial value of edge was x

So,

Initial Surface Area, A1=6x2

The edge increased by 50%,

so, the final edge length is, 3x/2

So, final Surface Area, A2=6(3x/2)2=6(9x2/4)

=6x2(9/4)=9/4(A1)

So, Increase in Surface Area, dA=A2−A1=9/4(A1)−A1

=A1(9/4−1)=A1(5/4)

So, the area increased by 5/4

Now, percentage increase will be (5/4)∗100=125%

So, the percentage increase in the Surface Area of the cube will be 125%.

I hope my answer was helpful.