Question

Instead of three bells, suppose that we have six bells, which start ringing together, and then ring at intervals of 2,4,6,8,10 and 12 minutes respectively.

In 30 hours, how many times will they ring together?


Instead of three bells, suppose that we have six bells, which start ringing together, and then ring at intervals of 2,4,6,8,10 and 12 minutes respectively.

In 30 hours, how many times will they ring together?

Answer 1

Answer:

In 30 hours, 16 times they will ring together.

Step-by-step explanation:

Six bells start ringing together, and then ring at intervals of 2,4,6,8,10 and 12 minutes respectively.

Hence, using LCM of the given numbers which is 120 we conclude that bell will ring together after 120seconds = 2minutes.

In 30minutes they will ring together in

$( \frac{30}{2} ) = 15$

15 and 1 (at the starting).

Hence, total number of bells together is

15 + 1 = 16

Hope this helps you.

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Answer 2

Answer:

Step-by-step explanation:

The time after which all six bells will toll together must be multiple of 2, 4, 6, 8, 10, 12

Therefore required time = LCM of time intervals

                                      = LCM (2, 4, 6, 8, 10, 12) = 120 sec

Therefore after 120 s all six bells will toll together

After each 120 s i.e. 2 min all bell are tolling together

Therefore in 30 min they will toll together ( 30\2+1)=16 times

1 is added as all the bells are tolling together at he start also i.e. 0th second